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(B) Chain isomerism occurs when compounds have the same molecular formula but different carbon chain structures (e.g.,straight chain vs. branched chai

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$I$ and $IV$

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(B) Chain isomerism occurs when compounds have the same molecular formula but different carbon chain structures (e.g.,straight chain vs. branched chain).$1$. $I$ $(CH_3-CH_2-CH_2-CH_2-OH)$ is a straight-chain alcohol (butan$-1-$ol).$2$. $IV$ $((CH_3)_2CH-CH_2-OH)$ is a branched-chain alcohol ($2$-methylpropan$-1-$ol).Both $I$ and $IV$ have the same molecular formula $(C_4H_{10}O)$ but differ in the arrangement of the carbon chain. Therefore,they represent chain isomerism.

Identify the pairs of compounds that represent chain isomerism among the following:
$I. CH_3-CH_2-CH_2-CH_2-OH$ (Butan$-1-$ol)
$II. CH_3-CH_2-CH(OH)-CH_3$ (Butan$-2-$ol)
$III. (CH_3)_3C-OH$ ($2$-Methylpropan$-2-$ol)
$IV. (CH_3)_2CH-CH_2-OH$ ($2$-Methylpropan$-1-$ol)

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Identify the pairs of compounds that represent chain isomerism among the following:$I. CH_3-CH_2-CH_2-CH_2-OH$ (Butan$-1-$ol)$II. CH_3-CH_2-CH(OH)-CH_3$ (Butan$-2-$ol)$III. (CH_3)_3C-OH$ ($2$-Methylpropan$-2-$ol)$IV. (CH_3)_2CH-CH_2-OH$ ($2$-Methylpropan$-1-$ol)